In which of the following reactions the product will be formed according to anti markovnikov rule :

C F_{3} C H = C H_{2} H C l \to

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C l C H = C H_{2} H C l \to

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C H_{3} O C H = C H_{2} H C l \to

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None

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Solution

The correct option is A $C F_{3} C H = C H_{2} H C l \to$
Due to strong $- I$ effect of $- C F_{3}$ group, the carbocation is formed at the terminal carbon.

Hence, the correct option is a.

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