Question

In which of the following sets the central atom of each member involves $s{p}^3$ hybridisation?

• A. $I{O}_4^{-},IC{l}_4^{-},I{F}_4^{+}$
• B. $Xe{O}_3,Xe{O}_4,Xe{F}_4$
• C. $S{O}_3,S{O}_3^{2-},S{O}_4^{2-}$
• D. $PC{l}_4^{+},B{F}_4^{-},Cl{O}_4^{-}$

Answer 1

The correct option is D $PC{l}_4^{+},B{F}_4^{-},Cl{O}_4^{-}$

Hybridisation is calculated by steric number rule.
Steric no. = no. of atoms attached to central atom + no. of lone pairs present on central atom.
Steric no. for $I{O}_4^{-}=4+0=4s{p}^3;$ Steric no. for $IC{l}_4^{-}=4+2=6s{p}^3{d}^2$
Steric no. for $I{F}_4^{+}=4+1=5s{p}^{3}d;$ Steric no. for $S{O}_3=3+0=3s{p}^2$
Steric no. for $S{O}_4^{2-}=4+0=4s{p}^3;$ Steric no. for $S{O}_3^{2-}=3+1=4s{p}^3$
Steric no. for $PC{l}_4^{+}=4+0=4s{p}^3;$ Steric no. for $B{F}_4^{-}=4+0=4s{p}^3$
Steric no. for $Xe{O}_3=3+1=4s{p}^3;$ Steric no. for $Xe{O}_4=4+0=4s{p}^3$
Steric no. for $Xe{F}_4=4+2=6s{p}^3{d}^2;$ Steric no. for $Cl{O}_4^{-}=4+0=4s{p}^3$