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Standard XII

Chemistry

Voids

In which of t...

Question

In which of the following solids, cations occupy tetrahedral voids?

N a C l

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C s B r

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Z n S

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N a_{2} O

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Solution

The correct option is C $Z n S$
In $Z n S$ type cations occupy tetrahedral voids.

$Z n^{2 +}$ at the alternate tetrahedral void

$S^{2 -}$ forms the FCC lattice.

The structure is also known as Zinc-Blende structure.

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Q5) in a crystalline solid , anions 'C' are arranged in cubic close packing cations 'A' occupy 50%of tetrahedral voids and cations 'B' occupy 50% of octahedral voids .what is the formula of the solid

Q. In which of the following compound, cations occupy alternate tetrahedral voids in cubic closed packing (ccp)?

Q. In a crystalline solid, anions

B

are arranged in ccp lattice and cations

A

occupy

50

% of the octahedral voids and

50

% of the tetrahedral voids. What is the formula of the solid?

Q. In a solid, oxide ions

(O^{2 -})

are arranged in ccp, cation

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Q. Assertion :The ratio of

Z n^{2 +}

and

F^{-}

per unit cell ZnS and

C a F_{2}

is 1:2. Reason: In ZnS,

Z n^{2 +}

ions occupy alternate tetrahedral voids and in

C a F_{2}, F^{-}

ions occupy all the tetrahedral voids of FCC unit cell.

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In which of the following solids, cations occupy tetrahedral voids?

The correct option is C ZnSIn ZnS type cations occupy tetrahedral voids.Zn2+ at the alternate tetrahedral voidS2− forms the FCC lattice.The structure is also known as Zinc-Blende structure.

The correct option is C $Z n S$
In $Z n S$ type cations occupy tetrahedral voids.

$Z n^{2 +}$ at the alternate tetrahedral void

$S^{2 -}$ forms the FCC lattice.

The structure is also known as Zinc-Blende structure.