In which of the following solvents, should KBr be soluble at 25∘C (D is the dielectric constant)?
A
C6H6(D=0)
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B
CH3OH(D=32)
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C
(CH3)2CO(D=21)
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D
CCl4(D=0)
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Solution
The correct option is CCH3OH(D=32) Like dissolves like. Since KBr is a polar ionic compound, it will be soluble in a polar solvent. The solvent with a higher value of dielectric constant will provide maximum solubility. It will be most soluble in polar solvents, i.e. with the highest value of D.