Question

In which of the following species is the bond angle maximum?

• A. $N{H}_3$
• B. $N{H}_4^{+}$
• C. $PC{l}_3$
• D. $SC{l}_2$

Answer 1

The correct option is B $N{H}_4^{+}$

The order of repulsion is:



In $N{H}_3$ and $PC{l}_3$ there are 3 bond pairs and 1 lone pair and so the hybridization is $s{p}^3$ with tetrahedral geometry and due to lp-bp repulsions, the shape is pyramidal and the bond angle is less than ${109.5}^o$

$SC{l}_2$ molecule has a bond angle of ${105}^o$ and has $s{p}^3$ hybridization.

$N{H}_4^{+}$ has 4 bond pairs and no lone pairs and is $s{p}^3$ hybridized with the geometry and shape both being tetrahedral with a bond angle of ${109.5}^o$ and so it has the highest bond angle among the four.