Question

In which of the following substances, sulphur has the lowest oxidation number?

• A. $H_{2}S{O}_4$
• B. $S{O}_2$
• C. $H_{2}S{O}_3$
• D. $H_{2}S$

Answer 1

The correct option is D $H_{2}S$

In $H_{2}S$, the oxidation state of sulfur is $-2$.

In other given compounds, sulfur has positive oxidation states.

The oxidation states of sulfur in $H_{2}S{O}_4$, $S{O}_2$ and $H_{2}S{O}_3$ are $+6$, $+4$ and $+4$ respectively.

Option D is correct.