In which of the following tables, $x$ and $y$ vary directly:
$x$ $3$ $5$ $8$ $11$
$y$ $4.5$ $7.5$ $12$ $16.5$

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Solution

$x = 3, y = 4.5 \frac{x}{y} = \frac{2}{3}$

$x = 5, y = 7.5 \frac{x}{y} = \frac{2}{3}$

$x = 8, y = 12 \frac{x}{y} = \frac{2}{3}$

$x = 11, y = 16.5 \frac{x}{y} = \frac{2}{3}$

All the values are in proportion.

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