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Oxides of Group 16

In which of t...

Question

In which of the following the bond angle is maximum:

H_{2} O

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H_{2} S

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S O_{2}

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S O_{3}

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Solution

The correct option is D $S O_{3}$
$S O_{3}$ has maximum angle

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Similar questions

S O_{2}

119^{\circ}

S O_{3}

120^{\circ}

S

S O_{2}

S O_{3}

s p^{2}

S O_{2}

119^{o}

S O_{3}

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S

S O_{2}

S O_{3}

s p^{2}

S + O_{2} ⟶ S O_{2}; Δ H = - 298.2 k J

S O_{2} + 1 / 2 O_{2} ⟶ S O_{3}; Δ H = - 98.7 k J

S O_{3} + H_{2} O ⟶ H_{2} S O_{4}; Δ H = - 130.2 k J

H_{2} + 1 / 2 O_{2} ⟶ H_{2} O; Δ H = - 287.3 k J

H_{2} S O_{4} a t 298 K

S + O_{2} \to {S O}_{2}; Δ H = - 298.2 k J

{S O}_{2} + \frac{1}{2} O_{2} \to S O_{3}; Δ H = - 98.7 k J

{S O}_{3} + H_{2} O \to H_{2} {S O}_{4}; Δ H = - 130.2 k J

H_{2} + \frac{1}{2} O_{2} \to H_{2} O; Δ H = - 227.3 k J

H_{2} {S O}_{4}

S + O_{2} \to {S O}_{2}; △ H = - 298.2 k J

{S 0}_{2} + 1 / 20_{2} \to {S O}_{3}; △ H = - 98.7 k J

S O_{3} + H_{2} O \to H_{2} {S O}_{4}; △ H = - 130.2 k J

H_{2} + 1 / 20_{2} \to H_{2} O; △ H = - 287 k J

H_{2} {S O}_{4}

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