In which of the following, the oxidation number of oxygen has been arranged in increasing order?

B a O_{2} < K O_{2} < O_{3} < O F_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

O F_{2} < K O_{2} < B a O_{2} < O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B a O_{2} < O_{3} < O F_{2} < K O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

K O_{2} < O F_{2} < O_{3} < B a O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $B a O_{2} < K O_{2} < O_{3} < O F_{2}$
Oxidation of oxygen are as follows:

$B a O_{2} (- 1), K O_{2} ⎛ ⎝ - \frac{1}{2} ⎞ ⎠, O_{3} (0), O F_{2} (+ 2)$ .

Suggest Corrections

Similar questions

O

O_{2}, O_{3}, O F_{2}

B a O_{2}

K O_{2}, N O_{2}, S O_{2}, B a O_{2}, C l O_{2}, O_{2}, N O, N_{2} O, O_{3}, C O

K O_{2}, A l O_{2}^{-}, B a O_{2}

N O_{2}^{+}

Among $K O_{2}$ , ${A l O_{2}}^{-}$ , $B a O_{2}$ , ${N O_{2}}^{+}$ unpaired electron is present in:

Among $K O_{2}, A l O_{2^{-}}, B a O_{2}$ and $N O_{2}^{+}$ unpaired electron is present in

Join BYJU'S Learning Program