Question

In which of the following years was the maximum parking fee collected ?

• A. 2005
• B. 2002
• C. 2001
• D. 2003

Answer 1

The correct option is D 2003

Calculate the parking fee for each of the years using the same logic as above 2005 = (16% of 200000) $\times$ 10 + (14% of 50000)$\times$ + (13% of 150000) $\times$ 30 + (15% of 75000) $\times$ 40 + (20% of 55000) $\times$ 50 = 2045000 2002 = (15% of 200000) $\times$ 10 + (16% of 50000)$\times$ 20 + (15% of 150000) $\times$ 30 + (17% of 75000) $\times$ 40 + (18% of 55000) $\times$ 50 = 2140000 2001 = (15% of 200000) $\times$ 10 + (16% of 50000) $\times$ 20 + (19% of 150000) $\times$ 30 + (17% of 75000) $\times$ 40 + (15% of 55000) $\times$ 50 = 2237500 2003 = (14% of 200000) $\times$ 10 + (17% of 50000) $\times$ 20 + (18% of 150000) $\times$ 30 + (16% of 75000) $\times$ 40 + (19% of 55000) $\times$ 50 = 2262500 Hence answer = 2003