In which one of the following compounds, the oxidation number of sulphur is the least

S O_{2}

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S O_{3}

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{N a}_{2} S O_{4}

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H_{2} S O_{4}

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Solution

The correct option is A $S O_{2}$
In ${S O}_{2}$ , $S$ is in oxidation state that is $+ I V$ and its highest oxidation state is $+ V I$ . Oxidation state is $+ V I$ in rest of the compounds.

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Similar questions

H_{2} S O_{4} + S O_{2} + N a_{2} c r o_{4} \to C r_{2} (S O_{4})_{3} + N a_{2} S O_{4}

x = H_{2} S O_{4}; y = H_{2} S O_{5}; z = H_{2} S_{2} O_{8}

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