In which one of the following equilibria, the increase of pressure over the equilibrium will favour the backward reaction?

Decomposition equilibrium of

H I

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Formation equilibrium of

S O_{3}

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Decomposition equilibrium of

N H_{3}

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Formation equilibrium of

P C l_{5}

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Solution

The correct option is C Decomposition equilibrium of $N H_{3}$
In the decomposition reaction of $N H_{3}$ the number of moles of products formed is greater than that of reactant involved.
$2 N H_{3} ⇌ N_{2} + 3 H_{2}$
According to Le-Chatelier's principle, the increase of pressure on a chemical equilibrium shift in that direction in which the number of gaseous molecules decreases and vice-versa thus in this reaction, increase in pressure favours the backward reaction.

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Similar questions

For the equilibrium $2 N O_{2} (g) ⇌ N_{2} O_{4} (g) + h e a t (14.6 k c a l)$ the increase in

temperature would

H I

H I

N H_{3}

N H_{3}

N_{2} (g) + 3 H_{2} (g) ⇌ 2 H N_{3} (g)

H_{2} X_{2} (g) + h e a t ⇌ 2 H X (g)

H X

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