You visited us 1 times! Enjoying our articles? Unlock Full Access!

Le Chatelier's Principle for Del N Equals to 0

In which one ...

Question

In which one of the following equilibrium, pressure has no effect :

P C l_{5} ⇌ P C l_{3} + C l_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 N H_{3} ⇌ N_{2} + 3 H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 S O_{2} + O_{2} ⇌ 2 S O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N_{2} + O_{2} ⇌ 2 N O

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $N_{2} + O_{2} ⇌ 2 N O$
With increase in pressure, the reaction goes in the direction where the number of moles of is decreasing.

In all reaction except option D, there is change in number of moles from reactants to products or vice-versa. so there will be influence of pressure to equilibrium of reaction.

change in number of moles :

option-A: 1 to 1+1
option-B: 2 to 1+3
option-C: 2+1 to 2
option-D: 1+1 to 2

In option D, since there is no change in no of moles pressure will have no effect.

Suggest Corrections

Similar questions

P {C l}_{5} \to P {C l}_{3} + {C l}_{2}

2 {S O}_{2} + O_{2} \to 2 {S O}_{3}

N_{2} + 3 H_{2} \to 2 {N H}_{3}

2 K C l O_{3} \to 2 K C l + 3 O_{2}

In which of the following reaction, the value of $K_{p}$ will be equal to $K_{c}$

N_{2} + 3 H_{2} ⇌ 2 {N H}_{3}

K_{1}

N_{2} + O_{2} ⇌ 2 N O

K_{2}

H_{2} + \frac{1}{2} O_{2} ⇌ H_{2} O

K_{3}

2 {N H}_{3} + \frac{5}{2} O_{2} ⇌ 2 N O + 3 H_{2} O

K_{1}, K_{2}

K_{3}

N_{2} + 3 H_{2} \to 2 N H_{3} - K_{1}

N_{2} + O_{2} \to 2 N O - K_{2}

H_{2} + 1 / 2 O_{2} \to H_{2} O - K_{3}

3 H_{2} + 5 / 2 O_{2} \to 2 N O + 3 H_{2} O

K_{1}, K_{2}, K_{3}

N_{2} + 3 H_{2} ⇌ 2 N H_{3}; K_{1}

N_{2} + O_{2} ⇌ 2 N O; K_{2}

H_{2} + \frac{1}{2} O_{2} \to H_{2} O; K_{3}

(K)

2 N H_{3} + \frac{5}{2} O_{2} K ⇌ 2 N O + 3 H_{2} O

Join BYJU'S Learning Program