The correct option is B [13π,1π]
y=x2sin1x+x3cos12x.
We will check f(a)=f(b) for each option.
Option A , [1π,2π]
f(1π)=0 and f(2π)=4√2+4ππ3
⇒, Rolle's theorem does not holds for [1π,2π]
Option B , [13π,1π]
f(13π)=0 and f(1π)=0
Hence, Rolle's theorem holds for [13π,1π]
It does not holds for other options.
Hence, option B is correct.