In which pair is the stronger bond found in the first species?
$I : O_{2}^{2 -}, O_{2}; I I : N_{2}, N_{2}^{+}; I I I : N O^{+}, N O^{-}$

I only

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II only

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I and II only

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II and III only

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Solution

The correct option is D II and III only
In pairs II and III only is the stronger bond found in the first species.
$I : O_{2}^{2 -}, O_{2}; I I : N_{2}, N_{2}^{+}; I I I : N O^{+}, N O^{-}$
The bond orders of $O_{2}^{2 -}, O_{2}; : N_{2}, N_{2}^{+}; N O^{+}, N O^{-}$ are 1, 2, 3, 2.5, 3 and 2 respectively.
Higher is the bond order, stronger is the bond formed.

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