In which pair(s) is/are the stronger bond found in the first species?

O_{2}

^{-}, O_{2}

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N_{2}, {N_{2}}^{+}

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N O^{+}, N O^{-}

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C O, {O_{2}}^{2 +}

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Solution

The correct options are
B $N_{2}, {N_{2}}^{+}$
C $N O^{+}, N O^{-}$
Bond order :
(A) $O_{2}^{-} = (10 - 7) / 2 = 1.5, O_{2} = (10 - 6) / 2 = 2$
(B) $N_{2} = (10 - 4) / 2 = 3, N_{2}^{+} = (9 - 4) / 2 = 2.5$
(C) $N O^{+} (10 - 4) / 2 = 3, N O^{-} = (10 - 6) / 2 = 2$
(D) $C O = (10 - 4) / 2 = 3, O_{2}^{2 +} = (10 - 4) / 2 = 3$

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Similar questions

Q. In which pair is the stronger bond found in the first species?

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Q. Consider the statements :
I. Bond length in

N_{2}^{+}

0.02 ˚ A

greater than in

N_{2}

.
II. Bond length in

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0.09 ˚ A

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III.

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Which of the following statements are true?

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In which pair(s) is/are the stronger bond found in the first species?

The correct options are B N2,N2+ C NO+,NO−Bond order :(A) O−2=(10−7)/2=1.5,O2=(10−6)/2=2(B) N2=(10−4)/2=3,N+2=(9−4)/2=2.5(C) NO+(10−4)/2=3,NO−=(10−6)/2=2(D) CO=(10−4)/2=3,O2+2=(10−4)/2=3