Question

In which quadrant does the terminal side of the angle ${120}^0$ lie?

• A. Quadrant I
• B. Quadrant II
• C. Quadrant III
• D. Quadrant IV

Answer 1

Answer: (B)

Quadrant II

$I\to 0^o-{90}^{o}II\to {90}^o-{180}^{o}III\to {180}^o-{270}^{o}IV\to {270}^o-{360}^o$

${120}^o\in [{90}^o,{180}^o]$

So, it will lie in $QuadrantII$