In which reaction incorrect product is formed ?

C H_{3} - C O C H_{3} Z n - H g - ---- \to conc. H C l C H_{3} - C H_{2} - C H_{3}

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C H_{3} - C H O Δ - ----- \to dil. N a O H C H_{3} - C H = C H - C H O

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P h - I + C_{2} H_{5} O N a \to P h - O C_{2} H_{5}

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H C H O conc. N a O H - ------ \to H C O O N a + C H_{3} O H

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Solution

The correct option is C $P h - I + C_{2} H_{5} O N a \to P h - O C_{2} H_{5}$
$P h - I + C_{2} H_{5} - O ⨁ N a \to N o S_{N} 2$ ,
$S_{N} 2$ nucleophilic subsitution at the $s p^{2}$ is not possible.
(A) Clemmensen Reduction
(B) Aldol condensation (self)
(D) Cannizzaro reaction

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{C H}_{3} C H (B r) {C H}_{2} {C H}_{3} A l c . K O H - ----- \to

{C H}_{3} C H = C H - {C H}_{3}

{C H}_{2} = C H {C H}_{2} {C H}_{3}

C H_{3} - C H_{2} - C H = C H - C H_{3} + H C l \to X + Y

A g N O_{3}

C H_{3} - C H = C H - C H_{3} H_{3} O^{+} - -- \to C H_{3} - C H_{2} - O H | C H - C H_{3}

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C H \equiv C H + H_{2} N i \to

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