In which step did the error occur first-6- 327-6- 3-27 Step 1-18-27 Step 2-1287 Step 3

Performing the calculation correctly, we find: 6× 327 =6×(3× 7)+27 =6×237 =1387 Comparing the correct steps with the given steps, we find: ∴The first err ...

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Standard VI

Mathematics

Addition of Decimals

In which step...

Question

In which step did the error occur first?

$6 \times 3 \frac{2}{7}$

$= (6 \times 3) + \frac{2}{7} ⟹ S t e p 1$

$= 18 + \frac{2}{7} ⟹ S t e p 2$

$= \frac{128}{7} ⟹ S t e p 3$

All steps are correct

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Solution

The correct option is B Step 1
Performing the calculation correctly, we find:

$6 \times 3 \frac{2}{7}$

$= 6 \times \frac{(3 \times 7) + 2}{7}$

$= 6 \times \frac{23}{7}$

$= \frac{138}{7}$

Comparing the correct steps with the given steps, we find:

$∴ The first error occured in S t e p 1$

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Similar questions

Q. In which step did the error occur first?

6 \times 3 \frac{2}{7}

= (6 \times 3) + \frac{2}{7} ⟹ S t e p 1

= 18 + \frac{2}{7} ⟹ S t e p 2

= \frac{128}{7} ⟹ S t e p 3

Select the step at which the error occurred first while adding 3/18 and 9/18.

Q. Simplify
(i)

10 \sqrt{2} - 2 \sqrt{2} + 4 \sqrt{32}

(ii)

\sqrt{48} - 3 \sqrt{72} - \sqrt{27} + 5 \sqrt{18}

(iii)

\sqrt[3]{16} + 8 \sqrt[3]{54} - \sqrt[3]{128}

Q. The following calculation was performed by James in his mathematics test. In which step did the error occur first?

\frac{8}{2^{2} + 1} + \frac{16}{2^{6} + 1} + \frac{32}{2^{14} + 1} + \frac{64}{2^{14} + 1} + \frac{128}{2^{18} + 1} =

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In which step did the error occur first? 6×327 =(6×3)+27⟹Step 1 =18+27⟹Step 2 =1287⟹Step 3

The correct option is B Step 1Performing the calculation correctly, we find: 6×327 =6×(3×7)+27 =6×237 =1387 Comparing the correct steps with the given steps, we find: ∴The first error occured in Step 1

In which step did the error occur first?

$6 \times 3 \frac{2}{7}$

$= (6 \times 3) + \frac{2}{7} ⟹ S t e p 1$

$= 18 + \frac{2}{7} ⟹ S t e p 2$

$= \frac{128}{7} ⟹ S t e p 3$

The correct option is B Step 1
Performing the calculation correctly, we find:

$6 \times 3 \frac{2}{7}$

$= 6 \times \frac{(3 \times 7) + 2}{7}$

$= 6 \times \frac{23}{7}$

$= \frac{138}{7}$

Comparing the correct steps with the given steps, we find:

$∴ The first error occured in S t e p 1$