In Wilkinson's catalyst, the hybridization of central metal ion and its shape are respectively:

{s p}^{3} d

, trigonal bipyramidal

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d^{2}, {s p}^{3}

, octahedral

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d {s p}^{2}

, square planar

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{s p}^{3}

, tetrahedral

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Solution

The correct option is B $d {s p}^{2}$ , square planar
Wilkinson's catalyst has 4 bond pairs.
Thus, it shows $d s p^{2}$ hybridization and has square planar geometry.

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