Question

In $Xe{F}_2,Xe{F}_4$, and $Xe{F}_6$, the number of lone pairs on $Xe$, is__________.

• A. $2,3,1$
• B. $1,2,3$
• C. $4,1,2$
• D. $3,2,1$

Answer 1

Answer: (D)

$3,2,1$

$Xe{F}_2$ has a linear shape. Its hybridization is $s{p}^{3}d$ which means it should have a trigonal bipyramidal shape. Since it has $3$ lone pairs, they occupy the equatorial triangle.

$Xe{F}_4$ has $s{p}^3{d}^2$ hybridization. It has a square planar shape and $2$ lone pair of electrons.

$Xe{F}_6$ has one lone pair of electrons. The $6$ out of $8$ electrons of Xenon are shared by $6$ atoms of fluorine.

Hence option D is the right answer.