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Question

In YDSE distance between the slits and screen is 1.5 m. When light of wavelength 500 nm is used, the 2nd bright fringe is obtained on the screen at a distance of 10 mm from the central bright fringe. What will be shift in position of 2nd bright fringe, if light of wavelength 550 nm is used ?

A
2 mm
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B
1 mm
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C
1.5 mm
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D
1.1 mm
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Solution

The correct option is B 1 mm
Given
D=1.5 mm λ1=500 nm, y1=10 mm,
λ2=550 nm, y2=?
As yλ
y1y2=λ1λ210y2=500550
y2=11 mmy2y1=1 mm

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