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Standard XII

Physics

YDSE Problems III

In YDSE exper...

Question

In YDSE experiment if slit separation is 0.4 mm and wavelength of light used is 400 nm, then number of maxima observed [for $θ = 37^{\circ}$ ] between C and P are

598

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749

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224

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500

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Solution

The correct option is A 598

Path difference $Δ x = d s i n θ \dots \dots \dots (1)$

$Δ x = n λ$

By (1) and (2)

$n λ = \frac{3 d}{5} \Rightarrow n = \frac{3 d}{5 λ} = 600$

Excluding at P and C, number of maxima = 598

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In YDSE experiment if slit separation is 0.4 mm and wavelength of light used is 400 nm, then number of maxima observed [for θ=37∘] between C and P are

The correct option is A 598 Path difference Δx=d sin θ………(1) Δx=nλ By (1) and (2) nλ=3d5⇒n=3d5λ=600 Excluding at P and C, number of maxima = 598

In YDSE experiment if slit separation is 0.4 mm and wavelength of light used is 400 nm, then number of maxima observed [for $θ = 37^{\circ}$ ] between C and P are

The correct option is A 598

Path difference $Δ x = d s i n θ \dots \dots \dots (1)$

$Δ x = n λ$

By (1) and (2)

$n λ = \frac{3 d}{5} \Rightarrow n = \frac{3 d}{5 λ} = 600$

Excluding at P and C, number of maxima = 598