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Byju's Answer
Standard XII
Physics
Maxima & Minima in YDSE
In YDSE if th...
Question
In YDSE if the source consists of two wave lengths λ1=4000a° and λ2=4002A° . Find the dis†an ce from centre where fringes disappear if d=1cm;D=1m
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Q.
In a YDSE, if the incident light consists of two wavelengths
λ
1
and
λ
2
, the slit separation is
d
, and the distance between the slit and the screen is
D
, the maxima due to each wavelength will coincide at a distance from the central maxima, given by
Q.
A beam of light consisting of wavelength 6000
˚
A
and 4500
˚
A
is used in a YDSE with D = 1m and d = 1mm. Find the least distance from central maxima, where bright fringes due to the two wavelengths coincide:
Q.
A light source, which emits two wavelengths
λ
1
=
400
nm and
λ
2
=
600
nm, is used in a Young's double slit experiment. If recorded fringe widths for
λ
1
and
λ
2
are
β
1
and
β
2
and the number of fringes for them within a distance y on one side of the central maximum are m
1
and m
2
, respectively, then
Q.
Wavelength of light used in an optical instrument are
λ
1
=
4000
˚
A
and
λ
2
=
5000
˚
A
then ratio of their respective resolving powers
(corresponding to
λ
1
and
λ
2
) is
Q.
In YDSE, when dichromatic source of light is used we get interference pattern which is obtained by combination of interference pattern due to each wavelength. A black line is obtained on screen where a minima due to each wavelength coincides. Similarly, when polychromatic source is taken say white light source, resulting interference pattern is superimposition of interference pattern from each wavelength as a result at which we get white central bright fringe surrounded by few coloured fringes on both sides of central bright fringe and then uniform illumination of screen. In a typical YDSE set up, distance between slits(D) is 1mm and screen is placed at a distance (D) of 1 m from slits. The source of light used is dichromatic emitting waves of wavelength
λ
1
= 500 nm and
λ
2
= 700 nm.
Fringe width due to
λ
1
is
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