In YDSE of equal width slits, if intensity at the centre of screen is I0, then intensity at a distance of β/4 from the central maxima is (β is the fringe width) :
A
I0
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B
I02
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C
I04
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D
I03
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Solution
The correct option is DI02
x=β4
Intensity at required point =Iocos2(πxβ)=Iocos2(π4)=Io2