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In YDSE setup...

Question

In YDSE setup, light of wavelength 640 nm is used with d = 0.8 mm and D = 1 m. If intensity at central maxima is $I_{0}$ and it's position is y = 0. Intensity at y = n mm is zero. Then find the minimum value of n (Answer upto 2 decimal places)

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Solution

$y = \frac{D λ}{2 d}$
$= \frac{1 \times 640 \times 10^{- 9}}{2 \times 0.8 \times 10^{- 3}}$
$= 400 \times 10^{- 6} m$
$y = 0.40 mm$

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