In YDSE, the source is placed symmetrical to the slits. If a transparent slab is placed in front of the upper slit, then(slab can absorb a fraction of light)

intensity of central maxima will not change

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intensity of central maxima may change

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central maxima will be shifted up

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intensity of dark fringes will be always zero

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Solution

The correct options are
B intensity of central maxima may change
C central maxima will be shifted up
Placing a slab in front of one slit shifts the central maxima.

Also, since a fraction of light is absorbed by the slab, the intensity of central maxima will also change.

As the intensity of light from one slit is different, destructive interference will not lead intensity 0. So dark fringes will also have some intensity,

Answer. B,C

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Similar questions

4000 \circ A

2 m

1 m m

1

2 m m, μ = 2), s l a b 2

1 m m, μ = 3)

3

4 m m, μ = \frac{3}{2})

(A) If slab $1$ is placed in front of slit $S_{1}$	(P) Central maxima at $C$
(B) If the slab $2$ is placed in front of slit $S_{2}$ along with condition (A)	(Q) Central maxima above $C$
(C) If slab $3$ is placed in front of slab $1$ along with condition (B)	(R) Fringe width is equal to $0.8 m m$
	(S) No. of fringes crossing central maxima as a result of slab placing is $5000$