CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
275
You visited us 275 times! Enjoying our articles? Unlock Full Access!
Question

In YDSE, when a glass plate of refractive index 1.5 and thickness t is placed in the path of one of the interfereing beams (wavelength λ), intensity at the position where central maximum occurred previously unchanged. The minimum thickness of the glass plate is

A
2λ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(2/3)λ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
λ/3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
λ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2λ
For minimum thickness, (n1)t=λ
t=λ(n1)=λ(1.51)=2λ

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Ray Diagrams of Spherical Mirrors
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon