In YDSE, when dichromatic source of light is used we get interference pattern which is obtained by combination of interference pattern due to each wavelength. A black line is obtained on screen where a minima due to each wavelength coincides. Similarly, when polychromatic source is taken say white light source, resulting interference pattern is superimposition of interference pattern from each wavelength as a result at which we get white central bright fringe surrounded by few coloured fringes on both sides of central bright fringe and then uniform illumination of screen. In a typical YDSE set up, distance between slits(D) is 1mm and screen is placed at a distance (D) of 1 m from slits. The source of light used is dichromatic emitting waves of wavelength λ1 = 500 nm and λ2= 700 nm.
Fringe width due to λ1 is
In YDSE, when dichromatic source of light is used we get interference pattern which is obtained by combination of interference pattern due to each wavelength. A black line is obtained on screen where a minima due to each wavelength coincides. Similarly, when polychromatic source is taken say white light source, resulting interference pattern is superimposition of interference pattern from each wavelength as a result at which we get white central bright fringe surrounded by few coloured fringes on both sides of central bright fringe and then uniform illumination of screen. In a typical YDSE set up, distance between slits(D) is 1mm and screen is placed at a distance (D) of 1 m from slits. The source of light used is dichromatic emitting waves of wavelength λ1 = 500 nm and λ2= 700 nm.
Fringe width due to λ1 is
The correct option is A 5×10−4m
ω=Dλ1d=1×500×10−91×10−3=5×10−4m
ω=Dλ1d=1×500×10−91×10−3=5×10−4m
