1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# In Young's double slit experiment, separation between the slits is halved and distance between slits and screen is doubled. The fringe width is

A
same.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
halved.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
onethird
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B quadrupledWe have fringe width, β=Dλdwhere D is the distance between the screen and the slits; d is the distance between the slits and λ is the wavelength.Given that the separation between the slits is halved, i.e., d′=d2 and distance between slits and screen is doubled, i.e., D′=2D.Hence now the modified fringe width (β′) is given byβ′=2Dλ(d2)=4Dλd=4β

Suggest Corrections
1
Join BYJU'S Learning Program
Related Videos
Fringe Width
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program