Question

In Young's double slit experiment, the 8th maximum with wavelength ${\lambda }_1$ is at a distance $d_1$ from the central maximum and the 6th with a wavelength ${\lambda }_2$ is at a distance $d_2$. Then $\left(d_1/d_2\right)$is equal to

• A. $\frac{4}{3}\left[\frac{{\lambda }_2}{{\lambda }_1}\right]$
• B. $\frac{4}{3}\left[\frac{{\lambda }_1}{{\lambda }_2}\right]$
• C. $\frac{3}{4}\left[\frac{{\lambda }_2}{{\lambda }_1}\right]$
• D. $\frac{3}{4}\left[\frac{{\lambda }_1}{{\lambda }_2}\right]$

Answer 1

The correct option is B $\frac{4}{3}\left[\frac{{\lambda }_1}{{\lambda }_2}\right]$

The correct answer should be option b.