wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In Young's double slit experiment the fringe width with light of wavelength 6000A is found to be 4.0 mm

A
fringe width if light of wavelength 4800 A is used is 3.2 mm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
distance between central maxima and first minimum is 3.2 mm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
central maxima is brighter than first maxima
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
brightness of first minimum is same as that of second minimum
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B fringe width if light of wavelength 4800 A is used is 3.2 mm

Given,
λ=6000A=6×107mβ=4mm=4×103mm
We know that fringe width β is
β=λDd
Here βλ
Now,
β1β2=λ1λ24×103β2=6×1074.8×107β2=4×1031.25=3.2mm
Correct option is A.



flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Intensity in YDSE
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon