Question

In young's double slit experiment , the intensity of light coming form the first slit is double the intensity from the second slit.The ratio of the maximum intensity to the minimum intensity on the interference fringe pattern observed is.

• A. 34
• B. 40
• C. 25
• D. 38

Answer 1

The correct option is A 34

$\frac{I_{max}}{I_{min}}={\left(\frac{\sqrt{\frac{I_1}{I_2}}+1}{\sqrt{\frac{I_1}{I_2}}-1}\right)}^2$

$={\left(\frac{\sqrt{2}+1}{\sqrt{2}-1}\right)}^2\approx 34$; (given $i_1=2i_2$)