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First Order Reaction

In Young's do...

Question

In Young's double slit experiment the intensity of the maxima is $I$ . If the width of each slit is doubled, the intensity of the maxima will be:

A

I / 2

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B

2 I

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C

4 I

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D

I

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Solution

The correct option is B $2 I$
$I = I_{m a x} = 4 I_{0}$
Now, $I_{0}$ is increased to $2 I_{0}$
So, $I_{m a x} = 4 (2 I_{0}) = 8 I_{0} = 2 I$
So, maximum intensity is $2 I$

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