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Question

# In Young's double-slit experiment, the interference pattern is found to have an intensity ratio between the bright and dark fringes as 9. This implies that

A
the intensities at the screen due to the two slits are 5 units and 4 units, respectively
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B
the intensities at the screen due to the two slits are 4 units and 1 units, respectively
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C
the amplitude ratio is 3
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D
the amplitude ratio is 2
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Solution

## The correct options are C the amplitude ratio is 2 D the intensities at the screen due to the two slits are 4 units and 1 units, respectivelyLet the souces have amplitudes a1,a2ImaxImin=(a1+a2)2(a1−a2)2=9Hence, a1+a2a1−a2=4⟹a1a2=2I1I2=a21a22=4

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