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Question

In Young's double slit experiment the slits are 0.5 mm apart and the interference is observed on a screen at a distance of 100 cm from the slit. It is found that the 9th bright fringe is at a distance of 7.5 mm from the second dark fringe from the centre of the fringe pattern. The wavelength of the light used is


A
25007A
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B
2500A
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C
5000A
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D
50007A
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Solution

The correct option is C 5000A
9β1.5β=7.5mm7.5β=7.5mmβ=1mmλDd=103=0.5×103×1031=5000A(c)

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