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Question
In Young's double slit experiment, two slits are separated by 3mm distance and illuminated by light of wavelength 480nm . The screen is at 2m from the plane of the slits. Calculate the separation between the 8th bright fringe and the 3rd dark fringe obtained with respect to central Bright fringe.
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Solution
The position of bright fringe is given as
xn=nλDd
The distance of the eighth fringe is given
as
x8=8×480×10−9m×2m3×10−3m
Similarly the distance of the third fringe
is given as
x3=3×480×10−9m×2m3×10−3m
The separation between the two is given as
x8−x3=5×480×10−9m×2m3×10−3m
Hence the separation is 1.6×10−9m
The position of bright fringe is given as
xn=nλDd
The distance of the eighth fringe is given as
x8=8×480×10−9m×2m3×10−3m
Similarly the distance of the third fringe is given as
x3=3×480×10−9m×2m3×10−3m
The separation between the two is given as
x8−x3=5×480×10−9m×2m3×10−3m
Hence the separation is 1.6×10−9m
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