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Question

In Young's double slit experiment using monochromatic light of wavelengths λ, the intensity of light at a point on the screen with path difference λ is M units. The intensity of light at a point where path difference is λ\3 is:

A
M2
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B
M4
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C
M8
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D
M16
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Solution

The correct option is C M4
Resultant intensity
IR=I1+I2+2I1I2cosθ

If path difference=λ,then phase difference 2π
IR=I+I+2I×Icos2π
= 4I
= M

Path difference λ3, then phase difference ϕ=2π3
IR"=I+I+2I×Icos2π3=I=M4
IR"=M4
Option B

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