In Young’s double slit experiment using two identical slits, the intensity at a bright fringe on the screen is I. If one of the slits is now closed the intensity of the same bright fringe on the screen will be:

I

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\frac{I}{2}

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\frac{I}{4}

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\frac{I}{\sqrt{2}}

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Solution

The correct option is C $\frac{I}{4}$
If amplitude is a then the intensity at a bright fringe on screen is $I = 4 a^{2}$ .
If one of the slit is closed no interference phenomenon takes place .
The intensity will be simply $a^{2}$ Thus Intensity is $I / 4$

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In Young’s double slit experiment using two identical slits, the intensity at a bright fringe on the screen is I. If one of the slits is now closed the intensity of the same bright fringe on the screen will be:

The correct option is C I4If amplitude is a then the intensity at a bright fringe on screen is I=4a2.If one of the slit is closed no interference phenomenon takes place . The intensity will be simply a2 Thus Intensity is I/4

The correct option is C $\frac{I}{4}$
If amplitude is a then the intensity at a bright fringe on screen is $I = 4 a^{2}$ .
If one of the slit is closed no interference phenomenon takes place .
The intensity will be simply $a^{2}$ Thus Intensity is $I / 4$