Question

In Young's double slit experiment, we get 10 fringes in the field of view of monochromatic light of wavelength 4000 $\stackrel{o}{A}$. If we use monochromatic light of wavelength 5000 $\stackrel{o}{A}$, then the number of fringes obtained in the same field of view is

• A. 8
• B. 10
• C. 40
• D. 50

Answer 1

The correct option is A 8

As $\beta \lambda$
$\therefore$ fringe width becomes $\frac{5}{4}$ times,
No, of fringes = $\frac{4}{5}\times 10=8$