Question

In Young's double slit experiment width sodium vapour lamp of wavelength 589 nm and the slits 0.589 mm apart, the half angular width of the central maximum is

• A. sin${}^{-1}\left(0.01\right)$
• B. sin${}^{-1}\left(0.0001\right)$
• C. sin${}^{-1}\left(0.001\right)$
• D. sin${}^{-1}\left(0.1\right)$

Answer 1

Answer: (C)

sin${}^{-1}\left(0.001\right)$

sin $\theta =\frac{\lambda }{d}=\frac{589\times {10}^{-9}}{0.589\times {10}^{-3}}={10}^{-3}=\frac{1}{1000}=0.001$