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Question

In Young's double slit experiment with monochromatic source of light of wavelength 6000 A, if the path difference at a point on the screen is 6 × 106m the number of the bright band formed at that point is:

A
2
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B
4
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C
6
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D
10
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Solution

The correct option is D 10
In YDSE,
Δx=nλ
where, Δx is path difference
n number of bright fringes
λ is wavelength of light
So, 6×106=n6000×1010
n=6×1066000×1010
=10

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