In Young's double slit experiment with monochromatic source of light of wavelength 6000 A∘, if the path difference at a point on the screen is 6 ×10−6m the number of the bright band formed at that point is:
A
2
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B
4
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C
6
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D
10
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Solution
The correct option is D 10 In YDSE, Δx=nλ where, Δx is path difference n number of bright fringes λ is wavelength of light So, 6×10−6=n6000×10−10 ⇒n=6×10−66000×10−10 =10