Question

In Young's double slit experiment with sodium vapour lamp of wavelength 589 tun and the slits 0.689 min apart, the half angular width of the central maximum is

• A. $si{n}^{-1}\left(0.01\right)$
• B. $si{n}^{-1}\left(0.0001\right)$
• C. $si{n}^{-1}\left(0.001\right)$
• D. $si{n}^{-1}\left(0.1\right)$

Answer 1

Answer: (C)

$si{n}^{-1}\left(0.001\right)$

In Young's double slit experiment half angular width is given by

$sin\theta =\frac{\lambda }{d}$

$sin\theta =\frac{589\times {10}^{-9}}{0.589\times {10}^{-3}}={10}^{-3}$

$\theta =si{n}^{-1}\left(0.001\right)$