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Standard XII

Physics

Intensity Amplitude Relationship

In Young's do...

Question

In Young's double slit expt. the distance between two sources is 0.1 mm. The distance of the screen from th source is 20 cm. Wavelength of light used is 5460 $o A$ . The angular position of the first dark fringe is

0.08

^{o}

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0.16

^{o}

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0.20

^{o}

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0.32

^{o}

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Solution

The correct option is C 0.16 $^{o}$
The position of n $^{t h}$ dark fringe. So position of first dark fringe in x $_{1}$ = $λ D / 2 d$ .
d = 20 cm, D = 0.1mm, $λ = 5460 o A$ , x $_{1}$ = 0.16

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In Young's double slit expt. the distance between two sources is 0.1 mm. The distance of the screen from th source is 20 cm. Wavelength of light used is 5460 oA. The angular position of the first dark fringe is

The correct option is C 0.16oThe position of nth dark fringe. So position of first dark fringe in x1 = λD/2d.d = 20 cm, D = 0.1mm, λ=5460oA, x1 = 0.16

In Young's double slit expt. the distance between two sources is 0.1 mm. The distance of the screen from th source is 20 cm. Wavelength of light used is 5460 $o A$ . The angular position of the first dark fringe is

The correct option is C 0.16 $^{o}$
The position of n $^{t h}$ dark fringe. So position of first dark fringe in x $_{1}$ = $λ D / 2 d$ .
d = 20 cm, D = 0.1mm, $λ = 5460 o A$ , x $_{1}$ = 0.16