In Young's double slit interference experiment, the wavelength of light used is 6000˙A. If the path difference between waves reaching a point P on the screen is 1.5 microns, then at that point P
A
Second maxima occurs
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Second minima occurs
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Third minima occurs
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Third maxima occurs
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C Third minima occurs λ=6000˙A,x=1.5μm=15000˙A For min. (dark band) x=(2n−1)λ2;15000=(2n−1)60002 15000=(2n−1)3000 5+1=2n n=62n=3 3rd dark band