In Zeisel's method for the determination of methoxy groups, a sample of 2.68 gm of a compound (A) gave 14.08 gm of AgI. If the molecular weight of compound (A) is 134, the number of $(- O C H_{3})$ group(s) in the compound (A) is:

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Solution

The correct option is A 3
The number of moles of organic compound $= \frac{2.68}{134} = 0.2$ mol.
The number of moles of silver iodide $= \frac{14.08}{234.77} = 0.06$
Thus, 0.2 moles of organic compound gives 0.6 moles of $A g I$ .
1 mole of organic compound will give 3 moles of $A g I$ .
Hence, the number of methoxy groups present in the organic compound is 3.

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In Zeisel's method for the determination of methoxy groups, a sample of 2.68 gm of a compound (A) gave 14.08 gm of AgI. If the molecular weight of compound (A) is 134, the number of (−OCH3) group(s) in the compound (A) is:

In Zeisel's method for the determination of methoxy groups, a sample of 2.68 gm of a compound (A) gave 14.08 gm of AgI. If the molecular weight of compound (A) is 134, the number of $(- O C H_{3})$ group(s) in the compound (A) is: