Incentre of triangle whose vertices are A(-36,7), B(20,7), C(0,-8), is
(-1,0)
∵a=BC=√(20−0)2+(7+8)2=25b=CA=√(−36−0)2+(7+8)2=39and c=AB=√(36+20)2+(7+7)2=56I=(25(−36)+39(20)+56(0)25+39+56,25(7)+39(7)+56(−8)25+39+56)I=(−1,0)Hence,(c) is the correct answer.