Incorrect order of the value of - 0 for the given complexes-

The correct option is A [Cr(NH_3)_6]^3+ S_0=[Cr(en)_3]^3+ gt;[Cr(NH_3)_6]^3+ This is because of chelation en being a bidentate ligand forms 3 me ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Central Atom and Ligands

Incorrect ord...

Question

Incorrect order of the value of $Δ_{0}$ for the given complexes?

[C r (N H_{3})_{6}]^{3 +} < [C r (e n)_{3}]_{3 +}]

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[C o (e n)_{3}]^{+ 3} > [R h (e n)_{3}]^{+ 3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[C o (H_{2} O)_{6}]^{+ 2} < [C o (H_{2} O)_{6}]^{+ 3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[N i c l_{6}]^{4} - < [N i (H_{2} O)_{6}]^{+ 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $[C r (N H_{3})_{6}]^{3 +} < [C r (e n)_{3}]_{3 +}]$
$S_{0} = {[C r {(e n)}_{3}]}^{3 +} > {[C r {(N H_{3})}_{6}]}^{3 +}$
This is because of chelation en being a bidentate ligand forms $3$ membered sings.
Hence, it has more energy.

Suggest Corrections

Similar questions

Correct increasing order for the wavelengths of absorption in the visible region for the complexes of $C o^{3 +}$ is

Q. The correct increasing order of wavelengths of absorption in the visible region for the complexes of

C o^{3 +}

is:

Q. Correct increasing order for the wavelength of absorbtion in the visible region for the complexes of

C o^{3 +}

is:

Q. Identify the correct order of wavelength of light absorbed for the following complex ions.

[C o (H_{2} O)_{6}]^{3 +}; C o (C N)_{6}]^{3 -}; [C o (I)_{6}]^{3 -}; [C o (e n)_{3}]^{3 +}

I II III IV

The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, $[C o (N H_{3})_{6}]^{3 +}, [C o (C N)_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{3 +}$
$[C o (N H_{3})_{6}]^{3 +}, [C o (C N)_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{3 +}$
(a) $[C o (C N)_{6}]^{3 -} > [C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +}$
(b) $[C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +} > [C o (N H_{3})_{6}]^{3 +}$
(c) $[C o (H_{2} O)_{6}]^{3 +} > [C o (N H_{3})_{6}]^{3 +} > [C o (C N)_{6}]^{3 -}$
(d) $[C o (C N)_{6}]^{3 -} > [C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +}$

Join BYJU'S Learning Program

Incorrect order of the value of Δ0 for the given complexes?

The correct option is A [Cr(NH3)6]3+<[Cr(en)3]3+]S0=[Cr(en)3]3+>[Cr(NH3)6]3+This is because of chelation en being a bidentate ligand forms 3 membered sings.Hence, it has more energy.

Incorrect order of the value of $Δ_{0}$ for the given complexes?

The correct option is A $[C r (N H_{3})_{6}]^{3 +} < [C r (e n)_{3}]_{3 +}]$
$S_{0} = {[C r {(e n)}_{3}]}^{3 +} > {[C r {(N H_{3})}_{6}]}^{3 +}$
This is because of chelation en being a bidentate ligand forms $3$ membered sings.
Hence, it has more energy.