Incorrect statement regarding X in the given reaction is: $B F_{3} + L i A l H_{4} \to (X) + L i F + A l F_{3}$

12 electrons are involved in bonding

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It has four (2 centre-2 electron) bonds

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It has two (three centre-two electron) bonds

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X does not react with ammonia

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Solution

The correct option is D X does not react with ammonia
Boron trifluoride reacts with lithium aluminium hydride in diethyl ether to give diborane
$B F_{3} + L i A l H_{4} \to B_{2} H_{6} + 3 L i [A l F_{4}]$
Thus, the X is diborane $(B_{2} H_{6})$
Diborane $(B_{2} H_{6})$ has following structure,
It has two $3$ - centered- $2$ - electrons bond and four $2$ -centered- $2$ -electrons bond. So total of $12$ electrons are involved in bonding.

Diborane react with $N H_{3}$ at different condition to gives various products like Boron nitride, Borazine and $[H_{2} B (N H_{3})_{2}]^{+} [B H_{4}]^{-} (ionic compound)$ .
Thus, (d) is incorrect.

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Similar questions

B F_{3} + L i A l H_{4} \to (X) + L i F + A l F_{3}

B F_{3} + L i A l H_{4} \to (x) + L i F + I F_{3}

B F_{3} + L i A l H_{4} \to (X) + L i F + A l F_{3}

B F_{3} + L i A l H_{4} E t h e r - -- \to (X) + L i F + A l F_{3}

N a B H_{4} + I_{2} \to X + Y + Z

B F_{3} + N a H 450 K - -- \to X + P

B F_{3} + L i A l H_{4} \to X + Q + R

X, Y, Z, P

Q

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