Question

Increase in the pressure for the following equilibrium : $H_{2}O\left(l\right)\rightleftharpoons H_{2}O\left(g\right)$, result in :

• A. formation of more $H_{2}O\left(l\right)$
• B. formation of more $H_{2}O\left(g\right)$
• C. increase in b.p of $H_{2}O\left(l\right)$
• D. decrease in b.p of $H_{2}O\left(l\right)$

Answer 1

Answer: (A), (C)

The correct options are
A formation of more $H_{2}O\left(l\right)$
C increase in b.p of $H_{2}O\left(l\right)$

As in this equilibrium, liquid converts into gas so increase in the pressure will favour reverse reaction; so formation of more $H_{2}O\left(l\right)$. Also, as we increase pressure boiling point of water increases.